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In the reaction A+BX2⟶AB+B, the rate of reaction is directly proportional to the concentration of A and independent on the concentration of B2. What is the rate law expression? -

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Question

In the reaction \[\ce{A + B2 -> AB + B}\], the rate of reaction is directly proportional to the concentration of A and independent on the concentration of B2. What is the rate law expression?

Options

  • rate = k[A] 

  • rate = k[B2]

  • rate = k[A] [B2]

  • rate = k[A]2 [B2]

MCQ

Solution

rate = k[A]

Explanation:

\[\ce{A + B2 -> AB + B}\]

Given Rate `∝` [A] and not on [B]

Rate depends on concentration of reactants.

Rate = k[A]

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Rate of Reaction and Reactant Concentration
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