Question

In the wave equation

`y = 0.5sin  (2pi)/lambda(400t - x)m`

the velocity of the wave will be ______.

Options

• 200 m/s

• `200sqrt2` m/s

• 400 m/s

• `400sqrt2` m/s

Answer 1

In the wave equation

`y = 0.5sin  (2pi)/lambda(400t - x)m`

the velocity of the wave will be 400 m/s.

Explanation:

Comparing the given `y  = 0.5sin ((2pi)/lambda400t - (2pi)/lambdax)` with the standard equation.

`omega = (2pi)/lambda400` and k = `(2pi)/lambda`

∴ velocity of the wave v = `omega/k = (2pi)/lambda 400/((2pi)/lambda)`

∴ v = 400 m/s