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In U238 ore containing Uranium the ratio of U234 to Pb206 nuclei is 3. Assuming that all the lead present in the ore is final stable product of U238. -

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In U238 ore containing Uranium the ratio of U234 to Pb206 nuclei is 3. Assuming that all the lead present in the ore is final stable product of U238. Half life of U238 to be 4.5 × 109 years and the age of ore is ______ × 109 years. (in 109 years)

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Solution

In U238 ore containing Uranium the ratio of U234 to Pb206 nuclei is 3. Assuming that all the lead present in the ore is final stable product of U238. Half life of U238 to be 4.5 × 109 years and the age of ore is 2 × 109 years. (in 109 years)

Explanation:

`"N"/("N"_0-"N") = 3/1`

⇒ `"N"/"N"_0 = 3/4`

`"N"/"N"_0 = 3/4 = "e"^(-lambda"t")` 

λt = loge 4/3

⇒ t = `((log_e4//3)/0.693)` T1/2

t = `4.5xx10^9[.1249/.3010]`

= 1.8678 × 109 years

≈ 2 × 109 years

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