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Question
In which of the following compounds the carbon marked with asterisk is expected to have greatest positive charge?
Options
*CH3 – CH2 – Cl
*CH3 – CH2 – Mg+ Cl–
*CH3 – CH2 – Br
*CH3 – CH2 – CH3
Solution
*CH3 – CH2 – Cl
Explanation:
Order of electronegativity of the attached group is as follows:
Cl > Br > C > Mg.
More electronegative group attached to the C will give more positive charge. Therefore, in case asterisk C will have greatest positive charge.
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Ionic species are stabilised by the dispersal of charge. Which of the following carboxylate ion is the most stable?
Identify the most stable species in the following set of ions giving reason:
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Identify the most stable species in the following set of ions giving reason:
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\[\begin{array}{cc}
\phantom{.........}\ce{O}\\
\phantom{.........}||\\
\ce{\underset{(I)}{CH2 = CH - C - H}}
\end{array}\]
\[\begin{array}{cc}
\phantom{.........}\ce{\overset{⊕}{O}}\\
\phantom{.........}|\\
\ce{\underset{(II)}{\overset{⊕}{C}H2 - CH = C - H}}
\end{array}\]
\[\begin{array}{cc}
\phantom{.........}\ce{\overset{⊕}{O}}\\
\phantom{.........}|\\
\ce{\underset{(III)}{\overset{Θ}{C}H2 - CH = C - H}}
\end{array}\]
