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Question
In which of the following species oxidation number of the element(s) is equal to + 4?
Options
[N = C = S]−
\[\ce{NO^+2}\]
C2H2
MCQ
Solution
[N = C = S]−
Explanation:
\[\ce{[\overset{-2}{N} = \overset{+4}{C} = \overset{-2}{S}]^-}\]
N > C and S > C
(in Electronegativity)
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Oxidation Number - Introduction
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