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Question
In Young's double silt experiment, two slits are d distance apart. The interference pattern is observed on a screen at a distance D from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light is ______.
Options
`d^2/D`
`d^2/(2D)`
`D^2/(2d)`
`D^2/d`
Solution
In Young's double silt experiment, two slits are d distance apart. The interference pattern is observed on a screen at a distance D from the slits. The first dark fringe is observed on the screen directly opposite one of the slits. The wavelength of light is `underlinebb(d^2/D)`.
Explanation:
According to the question,
Position of first dark fringe = d/2
For the nth dark fringe, `x_n = (2n - 1)(Dlambda)/(2d)`
Here, n = 1
∴ x1 = d/2
`(2 xx 1 - 1)(Dlambda)/(2d) = d/2 ⇒ lambda = d^2/D`