Question

In Young's double slit experiment, the 8^th maximum with wavelength λ₁​ is at a distance d₁​ from the central maximum and the 6^th maximum with a wavelength λ₂​ is at a distance d₂​. Then d₁​/d₂​ is equal to ______.

Options

• `4/3(lambda_2/lambda_1)`

• `4/3(lambda_1/lambda_2)`

• `3/4(lambda_2/lambda_1)`

• `3/4(lambda_1/lambda_2)`

Answer 1

In Young's double slit experiment, the 8^th maximum with wavelength λ₁​ is at a distance d₁​ from the central maximum and the 6^th maximum with a wavelength λ₂​ is at a distance d₂​. Then d₁​/d₂​ is equal to `underlinebb(4/3(lambda_1/lambda_2))`.

Explanation:

Position of the n^th maxima from central maxima is given by

x_n = `("n"lambda"D")/"d"`

⇒ x_n = ∝ n λ

⇒ `"d"_1/"d"_2=("n"_1lambda_1)/("n"_2lambda_2)`

= `(8lambda_1)/(6lambda_2)=4/3(lambda_1/lambda_2)`