Question

In Young's experiment, the distance between the slits is doubled and the distance between the slit and screen is reduced to half, then the fringe width ____________.

Options

• will not change

• will become half

• will be doubled

• will become 1/4^th times

Answer 1

In Young's experiment, the distance between the slits is doubled and the distance between the slit and screen is reduced to half, then the fringe width will become 1/4^th times.

Explanation:

`"W" = (lambda"D")/"d" and "W'" = (lambda"D")/"d"`

`"but  d'"  "d"/2 and "D'" = 2  "D"`

`therefore "W'" = (lambda ("D"))/(2(2"d")`

`= (lambda"D")/(4"d") = "W"/4`

`therefore "Fringe width will become"  1//4^"th" "times"`