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Question
Insert four A.M.s between 14 and -1.
Sum
Solution
Let the required arithmetic means (A.M.s) between `14 and -1` 'be `A_1,A_2,A_3 and A_4`
`⇒ 14,A_1,A_2,A_3,A_4 and -1 are in A.P`
`⇒14= "first term" `
`⇒-1=6^"th term of this A.P"`
`⇒-1=14+5d`
`⇒ 5d=-15`
`⇒ d=-3`
`⇒ A_1=14+d=14+(-3)=11`
`⇒A_2=14+2d=14+2(-3)=-8`
`⇒A_3=14+3d=14+3(-3)=5`
`⇒A_4=14+4d=14+4(-3)=2`
Hence, required A.M.s between `14 and -1=11,8,5 and 2`
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Simple Applications of Arithmetic Progression
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