Advertisements
Advertisements
Question
Integrate the following with respect to x:
`6/(1 + (3x + 2)^2) - 12/sqrt(1 - (3 - 4x)^2`
Solution
`int [6/(1 + (3x + 2)^2) - 12/sqrt(1 - (3 - 4x)^2)] "d"x`
= `6int 1/(1 + (3x + 2)^2) "d"x - 12int 1/sqrt(1 - (3 - 4x)^2) "d"x`
= `6/3 tan^-1 (3x + 2) (- 12)/(- 4) sin^-1 (3 - 4x) + "c"`
= `2 tan^-1 (3x + 2) + 3sin^-1 (3 - 4x) + "c"`
APPEARS IN
RELATED QUESTIONS
Integrate the following with respect to x:
`(x + 4)^5 + 5/(2 - 5x)^4 - "cosec"^2 (3x - 1)`
Integrate the following with respect to x:
`4 cos(5 - 2x) + 9"e"^(3x - 6) + 24/(6 - 4x)`
Integrate the following with respect to x:
`sec^2 x/5 + 18 cos2x + 10sec(5x + 3) tan(5x + 3)`
Integrate the following with respect to x:
`8/sqrt(1 - (4x)^2) + 27/sqrt(1 - 9x^2) - 15/(1 + 25x^2)`
Integrate the following with respect to x:
`1/3 cos(x/3 - 4) + 7/(7x + 9) + "e"^(x/5 + 3)`
