Advertisements
Advertisements
Question
Is -150 a term of the AP 11, 8, 5, 2, ……?
Solution
The given AP is 11, 8, 5, 2, ……
Here, a= 11and d = 8 - 11 = - 3
Let the nth term of the given AP be - 150. Then,
an = -150
⇒ 11+ (n-1) × (-3) = - 150 [ an = a + (n-1) d]
⇒ -3n +14 = -150
⇒ -3n = -164
⇒ n= `164/3 = 54 2/3`
But, the number of terms cannot be a fraction.
Hence, -150 is not a term of the given AP.
APPEARS IN
RELATED QUESTIONS
The sum of the first p, q, r terms of an A.P. are a, b, c respectively. Show that `\frac { a }{ p } (q – r) + \frac { b }{ q } (r – p) + \frac { c }{ r } (p – q) = 0`
Find the sum of the following APs.
−37, −33, −29, …, to 12 terms.
Find the sum of the following arithmetic progressions
`(x - y)^2,(x^2 + y^2), (x + y)^2,.... to n term`
Find the sum of the first 15 terms of each of the following sequences having the nth term as
bn = 5 + 2n
The first and last terms of an AP are a and l respectively. Show that the sum of the nth term from the beginning and the nth term form the end is ( a + l ).
Find the sum (−5) + (−8)+ (−11) + ... + (−230) .
The 9th term of an A.P. is 449 and 449th term is 9. The term which is equal to zero is
Find the sum of first 1000 positive integers.
Activity :- Let 1 + 2 + 3 + ........ + 1000
Using formula for the sum of first n terms of an A.P.,
Sn = `square`
S1000 = `square/2 (1 + 1000)`
= 500 × 1001
= `square`
Therefore, Sum of the first 1000 positive integer is `square`
The sum of the first 15 multiples of 8 is ______.
If the first term of an AP is –5 and the common difference is 2, then the sum of the first 6 terms is ______.