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Question
जर secθ = `25/7`, तर tanθ ची किंमत काढण्यासाठी खालील कृती पूर्ण करा.
कृती:
1 + tan2θ = sec2θ
∴ 1 + tan2θ = `square`
∴ `tan^2θ = 625/49 - square`
∴ `tan^2θ = (625 - 49)/49`
∴ `tan^2θ = (square/49)`
∴ tanθ = `square`
Activity
Solution
1 + tan2θ = sec2θ
∴ `1 + tan^2θ = bb((25/7)^2)`
∴ `tan^2θ = 625/49 - bb1`
∴ `tan^2θ = (625 - 49)/49`
∴ `tan^2θ = (bb576/49)`
∴ tanθ = `sqrt(576/49) = bb(24/7)`
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