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Question
Solve the following question and mark the best possible option.
Let A = { 3, 6, 9, 12, ......., 696, 699} & B = {7, 14, 21, .........., 287, 294}
Find no. of ordered pairs of (a, b) such that a ∈ A, b ∈ B, a ≠ b & a + b is odd.
Options
4879
4893
2436
2457
MCQ
Solution
A has `699/3` = 233 elements of which 116 are even & 117 are odd.
B has `294/7= 42` elements out of which 21 are even & 21 are odd.
A∩B = { 21, 42, ........, 273, 294}
∴ n(A ∩ B) = 14
For choice of a & b, 2 cases arise:-
Case- I: a is even & b is odd.
No. of possible cases = `""^116C_1 xx ""^21C = 116 xx 21`
Case-II: a is odd & b is even:-
No. of possible cases = `""^117C_1 xx ""^21C` = 117 x 21
But there are 14 cases where a = b & a, b, x A∩B.
So, required answer = 116 x 21 + 117 x 21 - 14 = 4879.
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Number System (Entrance Exam)
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