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Question
Let A and B be two events such that P(A) ≠ 1 and P(B) ≠ 0, then `"P"(bar"B"/bar"A")` = ______.
Options
`1 - "P"("B"/"A")`
`1 - "P"(bar"B"/"A")`
`(1 - "P"("A" ∪ "B"))/("P"(bar"A")`
`("P"(bar"B"))/("p"(bar"A"))`
MCQ
Fill in the Blanks
Solution
Let A and B be two events such that P(A) ≠ 1 and P(B) ≠ 0, then `"P"(bar"B"/bar"A")` = `(1 - "P"("A" ∪ "B"))/("P"(bar"A")`.
Explanation:
`"P"(bar"B"/bar"A") = ("P"(bar"A" ∩ bar"B"))/("P"(bar"A"))`
= `("P"(bar"A ∪ B"))/("P"(bar"A"))`
= `(1 - "P"("A" ∪ "B"))/("P"(bar"A"))`
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