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Question
Let S = `{((a_11, a_12),(a_21, a_22)): a_(ij) ∈ {0, 1, 2}, a_11 = a_22}`
Then the number of non-singular matrices in the set S is ______.
Options
27
24
10
20
Solution
Let S = `{((a_11, a_12),(a_21, a_22)): a_(ij) ∈ {0, 1, 2}, a_11 = a_22}`
Then the number of non-singular matrices in the set S is 20.
Explanation:
The matrices in the form
`[(a_11, a_12),(a_21, a_22)], a_(ij) ∈ {0, 1, 2}, a_11 = a_22` are
`[(0, 0//1//2),(0//1//2, 0)], [(1, 0//1//2),(0//1//2, 1)], [(2, 0//1//2),(0//1//2, 2)]`
At any place, 0/1/2 means 0, 1 or 2 will be the element at that place.
Hence there are total of 27 (= 3 × 3 + 3 × 3 + 3 × 3) matrices of the above form. Out of which the matrices which are singular are
`[(0, 0//1//2),(0, 0)], [(0, 0),(1//2, 0)], [(1, 1),(1, 1)], [(2, 2),(2, 2)]`
Hence there are total 7(= 3 + 2 + 1 + 1) singular matrices.
Therefore number of all non-singular matrices in the given form = 27 – 7 = 20