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Question
Let the tangent to the parabola S: y2 = 2x at the point P(2, 2) meet the x-axis at Q and normal at it meet the parabola S at the point R. Then, the area (in sq.units) of the triangle PQR is equal to ______.
Options
25
`25/2`
`15/2`
`35/2`
Solution
Let the tangent to the parabola S: y2 = 2x at the point P(2, 2) meet the x-axis at Q and normal at it meet the parabola S at the point R. Then, the area (in sq.units) of the triangle PQR is equal to `underlinebb(25/2)`.
Explanation:
Tangent at P: yy1 = 2a(x + x1)
y(2) = `2(1/2)(x + 2)`
⇒ 2y = x + 2
∴ Q = (–2, 0)
Slope of tangent P = `1/2`
Normal at P: y – 2 = `-1/((1/2))(x - 2)`
⇒ y – 2 = –2(x – 2) ...[∵ m1m2 = – 1]
⇒ y = 6 – 2x
∴ Now, solving with y2 = 2x ⇒ `"R"(9/2, -3)`
∴ Area(ΔPQR) = `1/2|(2, 2, 1),(-2, 0, 1),(9/2, -3, 1)|`
= `1/2|2(0 + 3) - 2(-2 - 9/2) + 1(+ 6 - 0)|`
= `25/2` sq.units