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Question
Let x = `[("a"^2"b"^2)/"c"]` be the physical quantity. If the percentage error in the measurement of physical quantities a, b and c is 2, 3 and 4 percent respectively then percentage error in the measurement of x is ______.
Options
7%
14%
21%
28%
MCQ
Fill in the Blanks
Solution
Let x = `[("a"^2"b"^2)/"c"]` be the physical quantity. If the percentage error in the measurement of physical quantities a, b and c is 2, 3 and 4 percent respectively then percentage error in the measurement of x is 14%.
Explanation:
Percentage error in the measurement of x
`(Deltax)/x=2(Delta"a")/"a"+2(Delta"b")/"b"+(Delta"c")/"c"`
= 2 × 2 + 2 × 3 + 4
= 4 + 6 + 4
= 14%
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