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Question
Let X = time (in minutes) that lapses between the ringing of the bell at the end of a lecture and the actual time when the professor ends the lecture. Suppose X has p.d.f.
f(x) = `{(kx^2"," 0 ≤ x ≤ 2), (0"," "othenwise"):}`
Then, the probability that the lecture ends within 1 minute of the bell ringing is ______
Options
`1/2`
`1/4`
`1/8`
`1/16`
Solution
Let X = time (in minutes) that lapses between the ringing of the bell at the end of a lecture and the actual time when the professor ends the lecture. Suppose X has p.d.f.
f(x) = `{(kx^2"," 0 ≤ x ≤ 2), (0"," "othenwise"):}`
Then, the probability that the lecture ends within 1 minute of the bell ringing is `underline(1/8)`.
Explanation:
Since, f(x) is the p.d.f. of X.
∴ `int_0^2 f(x)dx = 1`
⇒ `int_0^2(kx^2)dx = 1`
⇒ k`[x^3/3]_0^2 = 1`
⇒ `k = 3/8`
∴ Required probability = P(X ≤ 1) = `int_0^1f(x)dx`
= `int_0^1(kx^2)dx`
= `3/8int_0^1x^2dx`
= `3/8[x^3/3]_0^1`
= `3/8(1/3 - 0) = 1/8`