English

Limx→0xz2-(z-x)23(8xz-4x23+8xz3)4 is equal to -

Advertisements
Advertisements

Question

`lim_(x -> 0) (xroot(3)(z^2 - (z - x)^2))/(root(3)(8xz - 4x^2) + root(3)(8xz))^4` is equal to

Options

  • `z/(2^(11/3))`

  • `1/(2^(23/3 . z))`

  • `2^(21/3) z`

  • None of these

MCQ

Solution

`1/(2^(23/3 . z))`

Explanation:

`lim_(x -> 0) (xroot(3)(z^2 - (z - x)^2))/(root(3)(8xz - 4x^2) + root(3)(8xz))^4`

= `lim_(x -> 0) (xroot(3)(2xz - x^2))/(root(3)(x)root(3)(8z - 4x) + root(3)(8z) root(3)(x))^4`

= `lim_(x -> 0) (x^(4/3) root(3)(2z - z))/(x^(4/3) [root(3)(8z - 4x) + root(3)(8z)]^4)`

= `(root(3)(2z))/([2 root(3)(8z)]^4)`

= `1/(2^(23/3).z)`

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×