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Question
`lim_(x->1) (x^2 - 3x + 2)/(x^2 - 1)` = ?
Options
0
`(- 1)/2`
`(- 7)/3`
`(- 5)/2`
MCQ
Solution
`(- 1)/2`
Explanation:
`lim_(x->1) (x^2 - 3x + 2)/(x^2 - 1)`
`= lim_(x->1) ((x - 1)(x - 2))/((x - 1)(x + 1))`
`= lim_(x->1) (x - 2)/(x + 1)`
`= (- 1)/2`
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