Advertisements
Advertisements
Question
Magnetic induction produced at the centre of a circular loop carrying current is 'B'. The magnetic moment of the loop of radius 'R' is (µ0 = permeability of free space) ____________.
Options
`("BR"^3)/(2pimu_0)`
`(2pi"BR"^3)/(mu_0)`
`("BR"^2)/(2pimu_0)`
`(2pi"BR"^2)/(mu_0)`
MCQ
Fill in the Blanks
Solution
Magnetic induction produced at the centre of a circular loop carrying current is 'B'. The magnetic moment of the loop of radius 'R' is `(2pi"BR"^3)/(mu_0)`.
Explanation:
m = nIA
For coil, magnetic induction at the centre,
`"B" = (mu_0 "nI")/(2"R")`
`therefore "I" = ("B" xx 2"R")/(mu_0 "n")`
`"For n" = 1, "Area A" = pi"R"^2`
`"m" = ("B" xx 2"R")/(mu_0) xx pi"R"^2`
` = (2pi"BR"^3)/(mu_0)`
shaalaa.com
Axial Magnetic Field Produced by Current in a Circular Loop
Is there an error in this question or solution?
