Question

Metal A has an electronic configuration of 2, 8, 1 and metal B has 2, 8, 8, 2 which is more reactive metal.

Identify A and B and give their reactions with dil HCL and dil H2SO4 ?

Answer 1

Metal A is more reactive than Metal B.

Metal A is Na (Sodium). Metal B is Ca (Calcium).
Reaction with HCl:

`2Na + 2HCl → 2NaCl + H_2`

`Ca +2HCl → CaCl_2 + H_2`

Reaction with `H_2SO_4` :

`2Na + H_2SO_4 → Na_2SO_4 + H_2`

`Ca + H_2SO_4 → CaSO_4 + H_2`