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Mewa Lal Borrowed Rs 20000 from His Friend Rooplal at 18% per Annum Simple Interest. He Lent It to Rampal at the Same Rate but Compounded Annually. Find His Gain After 2 Years. - Mathematics

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Question

Mewa Lal borrowed Rs 20000 from his friend Rooplal at 18% per annum simple interest. He lent it to Rampal at the same rate but compounded annually. Find his gain after 2 years.

Numerical

Solution

SI for Mewa Lal \[= \frac{\text{ PRT }}{100}\]
\[ = \frac{20, 000 \times 18 \times 2}{100}\]
 = Rs 7, 200
Thus, he has to pay Rs 7, 200 as interest after borrowing.
CI for Mewa Lal = A - P
\[ = 20, 000 \left( 1 + \frac{18}{100} \right)^2 - 20, 000\]
\[ = 20, 000 \left( 1 . 18 \right)^2 - 20, 000\]
 = 27, 848 - 20, 000
 = Rs 7, 848
He gained Rs 7, 848 as interest after lending.
His gain in the whole transaction = Rs 7, 848 - Rs 7, 200
 = Rs 648

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Chapter 14: Compound Interest - Exercise 14.1 [Page 5]

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RD Sharma Mathematics [English] Class 8
Chapter 14 Compound Interest
Exercise 14.1 | Q 8 | Page 5

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