Question

\[\ce{C3H8O ->[{[O]}][K2Cr2O7/H2SO4] C3H6O ->[I2 + NaOH(aq.)] CHI3}\]

In this reaction the first compound is:

Options

• CH₃CH₂CH₂OH

• \[\begin{array}{cc}
  \ce{CH3-CH-CH3}\\
  |\phantom{..}\\
  \ce{OH}
  \end{array}\]

• CH₃OCH₂CH₃

• CH₃CH₂CHO

Answer 1

\[\begin{array}{cc}
\ce{CH3-CH-CH3}\\
|\phantom{..}\\
\ce{OH}
\end{array}\]

Explanation:

\[\begin{array}{cc}
\ce{CH3 - CH - CH3 ->[{[O]}][K2Cr2O7/H^+] CH3 - C - CH3 ->[I2 + NaOH] CHI3 + CH3 - C - Na}\\
\phantom{..}|\phantom{.............................}||\phantom{................................}||\phantom{}\\
\phantom{........}\ce{OH}\phantom{...........................}\ce{O}\phantom{............................}\ce{\underset{Yellow ppct}{O}\phantom{...}}
\end{array}\]