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Question
Obtain an expression for practical determination of end correction for a pipe closed at one end.
Numerical
Solution
In a pipe closed at one end, the fundamental mode corresponds to a node at the closed end and an antinode at the open end.
Resonant Length Condition:
For the fundamental frequency:
`L+e=λ/4`
λ = 4(L + e)
`f=v/(4(L+e))`
Thus, the total end correction for a pipe closed at one end is e.
Again, from experiments, e ≈ 0.6R.
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