Advertisements
Advertisements
Question
On a morning walk, three persons step off together and their steps measure 40 cm, 42 cm and 45 cm, respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps?
Solution
We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance.
For this, 40 = 2 × 2 × 2 × 5
42 = 2 × 3 × 7
And 45 = 3 × 3 × 5
∴ LCM(40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7
= 2520
Minimum distance each should walk is 2520 cm so that each can cover the same distance in complete steps.
APPEARS IN
RELATED QUESTIONS
Consider the number 6n where n is a natural number. Check whether there is any value of n ∈ N for which 6n is divisible by 7.
Determine the prime factorisation of each of the following positive integer:
20570
Write the exponent of 2 in the price factorization of 144.
If 13824 = 2a × 3b then find a and b
Find the least positive value of x such that 89 ≡ (x + 3) (mod 4)
The product of two consecutive natural numbers is always ______.
When a number is divided by 7, its remainder is always ______.
The HCF of the smallest 2-digit number and the smallest composite number is ______.
If two positive integers a and b are written as a = x3y2 and b = xy3, where x, y are prime numbers, then the result obtained by dividing the product of the positive integers by the LCM (a, b) is ______.
Three bells toll at intervals of 9, 12 and 15 minutes respectively. If they start tolling together, after what time will they next toll together?