Question

On Electrolysis of dilute sulphuric acid using platinum electrodes, the product obtained at the anode will be.

Options

• Hydrogen

• Oxygen

• Hydrogen sulphide

• Sulphur dioxide

Answer 1

Oxygen

Explanation:

Dissociation of sulfuric acid,

\[\ce{H2SO4 -> 2H+(aq) + SO^{-2}_{-4}(aq)}\]

Disssociation of water,

\[\ce{H2O -> H+(aq) + OH^{-}(aq)}\]

At Anode: \[\ce{4OH- -> 2H2O+(l) + O2(g) + 4e-}\]

At Cathode: \[\ce{2H+(aq) + 2e- -> H2(g)}\]