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One measure of average global temperature shows how each year varies from a base measure. The table shows results for several years. - Mathematics

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Question

One measure of average global temperature shows how each year varies from a base measure. The table shows results for several years.

Year 1958 1964 1965 1978 2002
Difference from base 0.10°C – 0.17°C – 0.10°C `(1/50)^circ`C 0.54°C

See the table and answer the following:

  1. Order the five years from coldest to warmest.
  2. In 1946, the average temperature varied by – 0.03°C from the base measure. Between which two years should 1946 fall when the years are ordered from coldest to warmest?
Sum

Solution

In the year 1978, temperature is `(1/50)^circ`C = 0.02°C

a. By observing coldest to warmest order is ascending order.

∴ – 0.17°C < – 0.10°C < 0.02°C < 0.10°C < 0.54°C

Order of years is 1964 < 1965 < 1978 < 1958 < 2002

b. In 1946, the temperature is – 0.03°C

We know that, – 0.03°C lies between – 0.10°C and `(1/50)^circ`C or 0.02°C

∴ – 0.10°C < – 0.03°C < 0.02°C

Hence, the coldest to warmest order including 1946 is 1964 < 1965 < 1946 < 1978 < 1958 < 2002.

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Chapter 2: Fractions and Decimals - Exercise [Page 47]

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NCERT Exemplar Mathematics [English] Class 7
Chapter 2 Fractions and Decimals
Exercise | Q 82. | Page 47
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