Question

One root of the equation `abs ((3"x" - 8, 3,3),(3, 3"x" - 8, 3),(3,3,3"x" - 8)) = 0` is ____________.

Options

• `2/3`

• `4/3`

• `1/3`

• 8

Answer 1

One root of the equation `abs ((3"x" - 8, 3,3),(3, 3"x" - 8, 3),(3,3,3"x" - 8)) = 0` is `underline(2/3)`.

Explanation:

`abs ((3"x" - 8, 3,3),(3, 3"x" - 8, 3),(3,3,3"x" - 8)) = 0`

Apply, R₁ → R₁ + R₂ + R₃,

`abs ((3"x" - 2, 3"x" - 2,3"x" - 2),(3, 3"x" - 8, 3),(3,3,3"x" - 8)) = 0`

`=> (3 "x" - 2) abs ((1,1,1),(3, 3"x" - 8,3),(3,3,3"x" - 8)) = 0`

 `=>` either (3x - 2) = 0

`(3 "x" - 2) abs ((1,1,1),(3, 3"x" - 8,3),(3,3,3"x" - 8)) = 0 => "x" = 2/3`