Question

Oxidation number of carbon in CH₂Cl₂ is

Options

• – 4

• + 4

• 0

• – 2

Answer 1

0

Explanation:

\[\begin{array}{cc}
\phantom{}\ce{\overset{+1}{H}}\\
\phantom{}|\\
\ce{\overset{+1}{H} - \overset{2-}{\underset{2+}{C}} - \overset{-1}{Cl}}\\
\phantom{}|\\
\phantom{}\ce{\overset{-1}{Cl}}
\end{array}\]  O.N. of C is zero