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Question
Picture based Question
Three conductors are joined as shown in the diagram
The current in conductor RS is 10 A. The current in conductor QR is 6 A. What will be the current in conductor PR
- 4 A
- 6 A
- 10 A
- 16 A
Solution
PR + OR = RS
PR + 6A = 10A
PR = 10A- 6A = 4A
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