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Question
Plot a graph showing variation of de Broglie wavelength λ versus `1/sqrtV` , where V is accelerating potential for two particles A and B, carrying the same charge but different masses m1, m2 (m1 > m2). Which one of the two represents a particle of smaller mass and why?
Solution
Given: Charge (q) is the same but masses of both the particles are different (m1 > m2).
The de Brogile wavelength given by
`lambda = h/sqrt(2mqV)`
The slope of the graph λ versus `1/sqrtV `is `h/sqrt(2mq)`
The slope of the smaller mass is larger; therefore, plot A in the above graph is for mass m2
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