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Question
Pratik heated 11.2 grams of element ‘M’ (atomic weight 56) with 4.8 grams of element 'N' (atomic weight 16) to form a compound. Find the empirical formula of the compound obtained by Pratik.
Solution
Given mass of M: 11.2 grams
Atomic weight of M: 56 g/mol
Moles of M = `"Mass of M"/"Atomic weight of M"`
= `(11.2 " g")/(56 " g/mol")`
= 0.2 mol
Given mass of N: 4.8 grams
Atomic weight of N: 16 g/mol
Moles of N = `"Mass of N"/"Atomic weight of N"`
= `(4.8 " g")/(16 " g/mol")`
= 0.3 mol
or
M : N = 2 : 3
Empirical formula is M2N3
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