Advertisements
Advertisements
Question
Pritam bought a plot of land for Rs 640000. Its value is increasing by 5% of its previous value after every six months. What will be the value of the plot after 2 years?
Solution
Given:
P = Rs 64, 000
R = 5 % for every six months
Value of the plot after two years = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[ \Rightarrow 64, 000 \left( 1 + \frac{5}{200} \right)^4 \]
\[ = 64, 000 \left( 1 . 025 \right)^4 \]
\[ = 706, 440 . 25\]
Thus, the value of the plot after two years will be Rs 706, 440.25.
APPEARS IN
RELATED QUESTIONS
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 5000, Rate = 10 paise per rupee per annum, Time = 2 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 2000, Rate = 4 paise per rupee per annum, Time = 3 years
At what rate percent will a sum of Rs 1000 amount to Rs 1102.50 in 2 years at compound interest?
The annual rate of growth in population of a certain city is 8%. If its present population is 196830, what it was 3 years ago?
The population of a certain city was 72000 on the last day of the year 1998. During next year it increased by 7% but due to an epidemic it decreased by 10% in the following year. What was its population at the end of the year 2000?
The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If its present value is Rs 43740, find its purchase price.
The value of a refrigerator which was purchased 2 years ago, depreciates at 12% per annum. If its present value is Rs 9680, for how much was it purchased?
Find the compound interest if the amount of a certain principal after two years is ₹ 4036.80 at the rate of 16 p.c.p.a.
The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.
The cost of a sewing machine is Rs 7,000. Its value depreciates at 8% p.a. Then the value of the machine after 2 years is Rs 5,924.80.