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Prove that the Average Power Taking by a Pure Capacitor Fed with a Sinusoidal Ac Supply in a Circuit is Zero. - Basic Electrical and Electronics Engineering

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Question

Prove that the average power taking by a pure capacitor fed with a sinusoidal ac supply in a circuit is zero.

Sum

Solution

PHASE DIFFERENCE
It is the angle between the voltage and current phasors.
๐œ‘ = 90°
POWER FACTOR
It is defined as the cosine of the angle between the voltage and current phasors.
Pf = cos๐œ‘ = cos(90°) = 0
POWER
Instantaneous power P is given by,

๐‘ = ๐‘ฃ๐‘–
๐‘ = ๐‘‰๐‘š๐‘ ๐‘–๐‘›๐œ”๐‘ก๐ผ๐‘šsin (๐œ”๐‘ก + 90)
๐‘ = ๐‘‰๐‘š๐ผ๐‘š๐‘ ๐‘–๐‘›๐œ”๐‘ก๐‘๐‘œ๐‘ ๐œ”๐‘ก

๐‘ =`(V_mI_m)/2`๐‘ ๐‘–๐‘›2๐œ”๐‘ก
The average power for one complete cycle, P =0
Hence, power consumed by a purely capacitive circuit is zero.

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Power and Power Factor
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2018-2019 (December) CBCGS
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