Question

Q 2

Answer 1

Let G₁, G₂, G₃, be three geometric means between a = `1/3` and b = 432

Then, `1/3` G₁, G₂, G₃, 432 is a G.P.
Thus, we have
First term = a =`1/3`
5^th term of the G.P. = ar⁴ = 432

`=>1/3xxr^4=432`
⇒ r⁴ = 1296
⇒ r⁴ = 6⁴
⇒ r = 6

∴ G₁ = ar = `1/3` x 6 = 2

 G₂ = ar² = `1/3` x 6 x 6 = 12

G₃ = ar³ = `1/3` x 6 x 6 x 6 = 72