Question

Q 3.2

Answer 1

Let G₁, G₂, G₃, G₄ be four geometric means between a = 3 and b = 96.

Then, 3, G₁, G₂, G₃, G₄, 96 is a G.P.
Thus, we have
First term = a = 3
6^th term of the G.P. = ar⁵ = 96

⇒ 3 x r⁵ = 96
⇒ r⁵ = 32
⇒ r⁵ = 2⁵
⇒ r = 2

∴ G₁ = ar = 3 x 2 = 6

 G₂ = ar² = 3 x 4 = 12

G₃ = ar³ = 3 x 8 = 24

G₄ = ar⁴ = 3 x 16 = 48