Question

Q.14 

 

Answer 1

Three digit numbers which leave the remainder 3 when divided by 5 are as follows: 

`103,108,113,118,123,..............998`

This from an A.P. with first term `a= 103`, common difference=5 and last term I=998

Let there be n terms in this A.P. 

`⇒ I=t_n=998`

`⇒ a+(n-1)d=998`

`⇒103+(n-1)xx5=998`

`⇒ (n-1)xx5=895`

`⇒n-1=179`

`⇒n=180`

`"∴ Required sum" =s=180/2(103+998)=90xx1101=99090`