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Question
Q.16
Sum
Solution
`"Sum of first 15 term of an A.P.=0"`
`⇒ S_15=0`
`⇒15/2[2a+14]=0`
`⇒ 2a+14d=0`
`⇒a+7d=0.................(1)`
`4^(th) "term" =t_4=12`'
⇒a+3d=12 ..............(2)
Subtracting (2) from (1), we get
`4d=-12⇒d=3`
`⇒ a+7xx(-3)=0`
`⇒a=21`
`∴ 12^(th) "term" = t_12=21+11xx(-3)=21-33=-12`
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