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Q.3 -

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Question

Q.3 

 

Sum

Solution

`1/a,1/b and 1/c` are in A.P

`⇒ 1/b-1/a=1/c-1/b`

`⇒(a-b)/(ab)=(b-c)/(bc)`

`⇒ac-bc=ab-ac`

`⇒ac+ac=ab+bc`

`⇒2ac=ab+bc`

`⇒2ca=ab+bc`

`⇒"bc, ca and ab are also in A,P."`

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Simple Applications of Arithmetic Progression
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