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Question
Q.3
Sum
Solution
`1/a,1/b and 1/c` are in A.P
`⇒ 1/b-1/a=1/c-1/b`
`⇒(a-b)/(ab)=(b-c)/(bc)`
`⇒ac-bc=ab-ac`
`⇒ac+ac=ab+bc`
`⇒2ac=ab+bc`
`⇒2ca=ab+bc`
`⇒"bc, ca and ab are also in A,P."`
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Simple Applications of Arithmetic Progression
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