Question

Q.3 

 

Answer 1

The given A.P.is ${\displaystyle 10,7,4,..............,-62}$

${\displaystyle Firstterm=10}$

${\displaystyle \text{Common difference}=7-10=-3}$

${\displaystyle \text{Last term}=1=-62}$

${\displaystyle \text{For the reverse A.P, first term=-62 and common differnce=3}}$

${\displaystyle \text{Thus,}{11}^{th}\text{term from the end of an given A.P}}$

${\displaystyle ={11}^{th}\text{term from the beginning of its reverse A.P}}$

${\displaystyle =-62+(11-1)\times \left(3\right)}$

${\displaystyle =-62+30}$

${\displaystyle =-32}$