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R−CHX2−CClX2−R→PeagentR−C≅ C−R. The reagent is:- -

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Question

\[\ce{R - CH2 - CCl2 - R ->[Peagent] R - C ≅ C - R}\]. The reagent is:-

Options

  • Na

  • HCl in H2O

  • KoH in L2 H5 OH

  • zn inalcohol

MCQ

Solution

KoH in L2 H5 OH

Explanation:

Dehydrohologenation reaction

\[\begin{array}{cc}
\ce{Cl}\phantom{...................................................}\\
|\phantom{....................................................}\\
\phantom{}\ce{RCH2 - C - R ->[C2H5OH + KOH][-KCl - H2O] RCH ≡ C - R ->[KoH + C2H5OH][-KCl - H2O] R - C ≡ C - R}\\
\phantom{}|\phantom{...........................}|\phantom{........................}\\
\phantom{..}\ce{Cl}\phantom{.........................}\ce{Cl}\phantom{.........................}
\end{array}\]

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