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Question
Rachana borrowed a certain sum at the rate of 15% per annum. If she paid at the end of two years Rs 1290 as interest compounded annually, find the sum she borrowed.
Solution
Let the money borrowed by Rachana be Rs x.
Then, we have:
\[CI = P \left( 1 + \frac{R}{100} \right)^n - P\]
\[1, 290 = x\left[ \left( 1 + \frac{15}{100} \right)^2 - 1 \right]\]
\[1, 290 = x\left[ 0 . 3225 \right]\]
\[x = \frac{1, 290}{0 . 3225}\]
\[ = 4, 000\]
Thus, Rachana borrowed Rs 4, 000.
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