Question

Sea water is found to contain 5.85% NaO and 9.50% MgCl₂ be weight of solution. The normal boiling point of sea water is ______°C assuming 80% ionisation for NaO and 50% ionisation of \[\ce{MgCl2 [Kb(H2O)}\] = 0.51 kg mole^-1 K].

Options

• 101.988°C

• 105.930°C

• 120.006°C

• 111.063°C

Answer 1

Sea water is found to contain 5.85% NaO and 9.50% MgCl₂ be weight of solution. The normal boiling point of sea water is 101.988°C assuming 80% ionisation for NaO and 50% ionisation of \[\ce{MgCl2 [Kb(H2O)}\] = 0.51 kg mole^-1 K].

Explanation:

\[\ce{100 gm -> 5.85 gm NaCl}\]

\[\ce{100 gm -> 9.5 gm MgCl2}\]

water = 100 - 5.85 - 9.5 = 84.65 gm

`Delta"T"_"b" = (0.51) [(0.18 + 0.15)/84.651)(1000)`

`= ((0.51)(0.33)(1000))/84.651`

T_b = 100 + 1.988

T_b = 101.988°C