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Question
`"sec" {"tan"^-1 (-"y"/3)}` is equal to ____________.
Options
`sqrt(9 + "y"^2)/9`
`sqrt(9 + "y"^2)/3`
`3/sqrt(9 + "y"^2)`
`9/sqrt(9 + "y"^2)`
MCQ
Fill in the Blanks
Solution
`"sec" {"tan"^-1 (-"y"/3)}` is equal to `underline(sqrt(9 + "y"^2)/3)`.
Explanation:
as sec `("tan"^-1 "y"/3) = sqrt(1 + "tan"^2 ("tan"^-1 "y"/3))`
`= sqrt(1 + "y"^2/9)`
`= sqrt((9 + "y"^2)/3)`
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