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Question
Select the most appropriate option.
For vaporization of water at 1 bar, ΔH = 40.63 kJ mol–1 and ΔS = 108.8 J K–1 mol–1 . At what temperature, ΔG = 0?
Options
273.4 K
393.4 K
373.4 K
293.4 K
Solution
373.4 K
Explanation:
Temperature at which reaction is at equilibrium (ΔG = 0) is,
T = `(triangle "H")/(triangle "S") = (40.63 "kJ mol"^-1)/(108.8 xx 10^-3 "kJ K"^-1) = 373.4 "K"`
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