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Question
Select the rate law that corresponds to the data shown for the following reaction:
Exp. | [A] mol dm−3 |
[B] mol dm−3 |
Initial Rate mol dm−3 |
1. | 0.012 | 0.035 | 0.10 |
2. | 0.024 | 0.070 | 0.80 |
3. | 0.024 | 0.035 | 0.10 |
4. | 0.012 | 0.070 | 0.80 |
Options
Rate = k[B]3
Rate = k[B]4
Rate = k[A] [B]
Rate = k[A] [B]3
Solution
Rate = k[B]3
Explanation:
When the concentration of B remains constant while the concentration of A varies, the rate of the reaction remains constant, as shown in experiments 1 and 3 or 2 and 4. As a result, the pace of the reaction is independent of A concentration. The rate of the reaction increases from 0.1 to 0.8 when the concentration of A is kept constant and the concentration of B is doubled, as shown in experiments 1 and 4. The new rate is eight times higher than the previous one. Hence The reaction rate is proportional to the cube of the concentration of B. (∵ 23 = 8)
Hence, the rate law is rate = k[B]3