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Show Graphically that the System of Equations 3x - Y = 5, 6x - 2y = 10 Has Infinitely Many Solutions. - Mathematics

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Question

Show graphically that the system of equations 3x - y = 5, 6x - 2y = 10 has infinitely many solutions.

Solution

On a graph paper, draw a horizontal line X'OX and a vertical line YOY' representing the x-axis and y-axis, respectively.
                           Graph of 3x - y = 5
3x - y = 5
⇒y = 3x -5 …(i)
Putting x = 1, we get y = -2
Putting x = 0, we get y = -5
Putting x = 2, we get y = 1
Thus, we have the following table for the equation 3x - y = 5

 x 1 0 2
y -2 -5 1

Now, plot the points A(1, -2), B(0, -5) and C(2, 1) on the graph paper.
Join AB and AC to get the graph line BC. Extend it on both ways.
Thus, the line BC is the graph of 3x - y = 5.
                               Graph of 6x - 2y = 10
6x - 2y = 10

⇒ 2y = (6x – 10)

⇒ y =`( 6x−10)/2`                        …(ii)

Putting x = 0, we get y = -5
Putting x = 1, we get y = -2
Putting x = 2, we get y = 1
Thus, we have the following table for the equation 6x - 2y = 10.

 x 0 1 2
y -5 -2 1

These are the same points as obtained for the graph line of equation (i).

It is clear from the graph that these two lines coincide.
Hence, the given system of equations has infinitely many solutions.

 

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Chapter 3: Linear Equations in two variables - Exercises 1

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RS Aggarwal Mathematics [English] Class 10
Chapter 3 Linear Equations in two variables
Exercises 1 | Q 23
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