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Question
Show that the following statement pattern is a contingency:
(p→q)∧(p→r)
Sum
Solution
p | q | r | p→q | p→r | (p→q)∧(p→r) |
T | T | T | T | T | T |
T | T | F | T | F | F |
T | F | T | F | T | F |
T | F | F | F | F | F |
F | T | T | T | T | T |
F | T | F | T | T | T |
F | F | T | T | T | T |
F | F | F | T | T | T |
The truth values in the last column are neither all T nor all F. Hence, it is contingence.
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