Advertisements
Advertisements
Question
Show that x = −3 is a solution of x2 + 6x + 9 = 0.
Solution
Given that the equation x2 + 6x + 9 = 0.
`x^2 + 3x + 3x + 9 = 0`
x (x+3) + 3 (x+3) = 0
(x + 3) (x+3) = 0
(x + 3)2 = 0
Square root both side, we get
(x+3) = 0
x = -3
Therefore, x = -3 is the solution of given equation.
Hence, proved.
APPEARS IN
RELATED QUESTIONS
Solve for x: `(x-3)/(x-4)+(x-5)/(x-6)=10/3; x!=4,6`
Solve the following quadratic equations by factorization:
4x2 + 5x = 0
Solve the following quadratic equations by factorization:
9x2 − 3x − 2 = 0
Solve the following quadratic equations by factorization:
`3x^2-2sqrt6x+2=0`
The product of two successive integral multiples of 5 is 300. Determine the multiples.
If \[1 + \sqrt{2}\] is a root of a quadratic equation will rational coefficients, write its other root.
Solve the following equation by factorization
3(x – 2)2 = 147
Find two consecutive integers such that the sum of their squares is 61
Solve the following equation by factorisation :
2x2 + ax – a2= 0
Find a natural number whose square diminished by 84 is equal to thrice of 8 more than the given number.